Specialist2024 NHT Exam 2 Section A · Q5CAS active1 mark

Solutions of a complex quadratic given its discriminant

For $z \in \C$ and $a \in \R$ , the discriminant of the quadratic equation $az^2 - aiz - 5 = 0$ is $36$ .

The possible solutions for $z$ to $az^2 - aiz - 5 = 0$ are

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\frac{1}{2}(\pm 3 + i)

\frac{1}{6}(\pm 1 + 3i)

\frac{1}{6}(\pm 3 + i)

\frac{1}{2}(\pm 1 + 3i)

\frac{1}{2}(\pm 3 - i)

\frac{1}{6}(\pm 1 - 3i)

\frac{1}{6}(\pm 3 - i)

\frac{1}{2}(\pm 1 + 3i)

\frac{1}{6}(\pm 3 - i)

\frac{1}{2}(\pm 1 - 3i)

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