Specialist2025 NHT Exam 2 Section A · Q16CAS active1 mark

Scalar product of cross products of perpendicular vectors

Consider two vectors $\tvec{a}$ and $\tvec{b}$ such that $|\tvec{a}| > 0$ , $|\tvec{b}| > 0$ and $\tvec{a} \cdot \tvec{b} = 0$ .

The expression $(\tvec{a} \times \tvec{b}) \cdot (\tvec{b} \times \tvec{a})$ is equivalent to

1 mark

-|\tvec{a}||\tvec{b}|

-|\tvec{a}|^2|\tvec{b}|^2

|\tvec{a}||\tvec{b}|

|\tvec{a}|^2|\tvec{b}|^2

Hints, answer checking and worked solutions come with a Season Pass.