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Specialist2023 Exam 2 Section A · Q10CAS active1 mark

Reduction formula by integration by parts

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If $I_n = \int_0^1 \left((1-x)^n e^x\right) dx$ , where $n \in N$ , then for $n \geq 1$ , $I_n$ equals

1 mark

A

-1 + nI_{n-1}

B

-1 - nI_{n-1}

C

-1 - nI_{n-1}

D

-nI_{n-1}

E

(1-x)^n e^x + nI_{n-1}

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