Specialist2024 NHT Exam 2 Section A · Q4CAS active1 mark

Trigonometric equation reduced to a quadratic in tan

The solutions of $\dfrac{1+5\sin(x)\cos(x)}{\cos^2(x)}-7=0$ can be found by solving

1 mark

\left(\tan(x)-2\right)\left(\tan(x)+3\right)=0

\left(\tan(x)-1\right)\left(\tan(x)+7\right)=0

\left(\tan(x)-3\right)\left(\tan(x)-2\right)=0

\left(\tan(x)-1\right)\left(\tan(x)+6\right)=0

\left(\tan(x)+1\right)\left(\tan(x)+6\right)=0

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