Specialist2025 NHT Exam 2 Section A · Q10CAS active1 mark

Surface area of revolution of a cubic

The curve given by $y = \frac{1}{3}x^3$ , where $x \in [0, 1]$ , is rotated about the $x$ -axis to form a surface of revolution.

The area of this surface is

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\frac{2\sqrt{2}\pi}{9}

\frac{\pi}{9}\left(2\sqrt{2} - 1\right)

\frac{\pi}{18}\left(2\sqrt{2} - 1\right)

\frac{4\pi}{9}\left(2\sqrt{2} - 1\right)

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