Methods2023 Exam 2 Section A · Q19CAS active1 mark

Quadratic with one positive and one negative root

Find all values of $k$ , such that the equation $x^2 + (4k + 3)x + 4k^2 - \frac{9}{4} = 0$ has two real solutions for $x$ , one positive and one negative.

1 mark

k > -\frac{3}{4}

k \geq -\frac{3}{4}

k > \frac{3}{4}

-\frac{3}{4} < k < \frac{3}{4}

k < -\frac{3}{4}

k > \frac{3}{4}

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